4. Temperature
Homework Answers
Absorb Incident radiant onorgy Reflected Emitted Absorbed Retained Black Black Incident radiant energy Reflected Emitte Retained...
Absorb Incident radiant onorgy Reflected Emitted Absorbed Retained Black Black Incident radiant energy Reflected Emitte Retained Absorbed Silver coated Silver coated A person with a surface area of 1.20 m2, and a skin temperature of 27 °C, is in a room that is at a temperature of 17.6 °C. The emissivity of the skin is 0.895, The Stefan-Boltzmann constant is 5.67 x 10-8 W/(m2K). (a) How much energy is radiated by the person in 1 minute? Keep 2 decimal places....
Find the radius RRigel of the star Rigel, the bright blue star in the constellation Orion...
Find the radius RRigel of the star Rigel, the bright blue star in the constellation Orion that radiates energy at a rate of 2.7×1031W and has a surface temperature of 11,000 K. Assume that the star is spherical. Use σ=5.67×10−8W/m2⋅K4 for the Stefan-Boltzmann constant and express your answer numerically in meters to two significant figures.
As much detail as possible would be greatly appreciated! The question is: Assuming the Earth's surface...
As much detail as possible would be greatly appreciated! The question is: Assuming the Earth's surface and the atmospheric layers act as perfect black bodies and that Earth has two layers of atmosphere and they are identical find the temperature at each layer and on the surface. Today's solar constant=1367Wm^2. Albedo of Earth=0.3. Stefan Boltzmann Constant=5.67*10^-8.
The energy radiated per unit surface area (across all wavelengths) for a black body with temperature...
The energy radiated per unit surface area (across all wavelengths) for a black body with temperature 2200. Use 5.67 x 10-8 for the Stefan-Boltzmann constant. The Stefan-Boltzmann Law describes the power radiated from a black body in terms of its temperature. Specifically, the total energy radiated per unit surface area of a black body across all wavelengths per unit time is proportional to the fourth power of the black body's thermodynamic temperature
How much power (power is the energy per second) is radiated by the person
Radiation of Energy The rate of heat transfer by emitted radiation is determined by the Stefan-Boltzmann law of radiation: = aeAT4 where o 5.67x10-8 J/s - m2 K is the Stefan-Boltzmann constant, A is the surface area of the object, and T is its absolute temperature in kelvin. The symbol e stands for the emissivity of the object, which is a measure of how well it radiates An ideal jet-black (or black body) radiator has e 1,whereas a perfect reflector has...
The filament in a light bulb has a diameter of 0.050 mm and an emissivity of...
The filament in a light bulb has a diameter of 0.050 mm and an emissivity of 1.0. The temperature of the filament is 3000°C. What should be the length of the filament so it will transfer heat at a rate of 60 J/s (i.e. Watts, W) via radiation? The Stefan-Boltzmann constant is 5.670 × 108 W/m2, K. 11 cm 8.6 cm 9.4 cm 5.9 cm
The filament of a 75-W light bulb is at a temperature of 3,650 K. Assuming the...
The filament of a 75-W light bulb is at a temperature of 3,650 K. Assuming the filament has an emissivity e = 0.6, find its surface area.
A perfect emitter with a surface area of 1(104) m2 has a temperature of 10,000K. Calculate...
A perfect emitter with a surface area of 1(104) m2 has a temperature of 10,000K. Calculate its radiant energy in watts. Stefan-Boltzmann's constant is 5.67(10-8) J/(s-m2-K4
An animal's body has a skin temperature of 33 °C and is the room temperature where...
An animal's body has a skin temperature of 33 °C and is the room temperature where the walls are at temperature 29 °C. If the emissivity is 1 and the body area is 1.5 m2. What is the rate of heat transfer by radiation? ( Stefan-Boltzmann constant = 5.67 x 10 -8 J/s m?k4) 42 W 38 W 72 W O 54 W O 63 W
5 and 7 Question 5 3 ptgu HC Calculate the blackbody surface temperature of Mars (3...
5 and 7
Question 5 3 ptgu HC Calculate the blackbody surface temperature of Mars (3 sig figs, answer in °C). Solar Flux on Mars (Fs) = 590 W m2 Stefan-Boltzmann constant (0) = 5.67 x 108W m2 K4 Earth's radius = 6.4 x 10 m Assume Mars' albedo = Earth's Albedo (It is worth thinking about whether this is a good assumption, or not! Question 6 O pts Upload a picture of your work from question 5. This is...
Absorb Incident radiant onorgy Reflected Emitted Absorbed Retained Black Black Incident radiant energy Reflected Emitte Retained Absorbed Silver coated Silver coated A person with a surface area of 1.20 m2, and a skin temperature of 27 °C, is in a room that is at a temperature of 17.6 °C. The emissivity of the skin is 0.895, The Stefan-Boltzmann constant is 5.67 x 10-8 W/(m2K). (a) How much energy is radiated by the person in 1 minute? Keep 2 decimal places....
Radiation of Energy The rate of heat transfer by emitted radiation is determined by the Stefan-Boltzmann law of radiation: = aeAT4 where o 5.67x10-8 J/s - m2 K is the Stefan-Boltzmann constant, A is the surface area of the object, and T is its absolute temperature in kelvin. The symbol e stands for the emissivity of the object, which is a measure of how well it radiates An ideal jet-black (or black body) radiator has e 1,whereas a perfect reflector has...
The filament in a light bulb has a diameter of 0.050 mm and an emissivity of 1.0. The temperature of the filament is 3000°C. What should be the length of the filament so it will transfer heat at a rate of 60 J/s (i.e. Watts, W) via radiation? The Stefan-Boltzmann constant is 5.670 × 108 W/m2, K. 11 cm 8.6 cm 9.4 cm 5.9 cm
An animal's body has a skin temperature of 33 °C and is the room temperature where the walls are at temperature 29 °C. If the emissivity is 1 and the body area is 1.5 m2. What is the rate of heat transfer by radiation? ( Stefan-Boltzmann constant = 5.67 x 10 -8 J/s m?k4) 42 W 38 W 72 W O 54 W O 63 W
5 and 7
Question 5 3 ptgu HC Calculate the blackbody surface temperature of Mars (3 sig figs, answer in °C). Solar Flux on Mars (Fs) = 590 W m2 Stefan-Boltzmann constant (0) = 5.67 x 108W m2 K4 Earth's radius = 6.4 x 10 m Assume Mars' albedo = Earth's Albedo (It is worth thinking about whether this is a good assumption, or not! Question 6 O pts Upload a picture of your work from question 5. This is...
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