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DO Be sure to review Examples 25 8 and 25.9 (Section 25.5) before attempting these problems. Part 3 Part 1 The current is 0.7
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Griven R NYV I= 0.70A R = 16-12 V = 12V mort Ro v IR Battery che Potential differenu 10.71116) a 088 = 11-36 V Battery Voltag

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