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Chapter 31, Problem 024 GO A single-loop circuit consists of a 7.2 2 resistor, 12.1 H inductor, and a 3.3 uF capacitor. Initi

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Answer #1

chare after 'N' cycles

t = N * T

where T = 2\pi / w

so,

q = Qe-Rt / 2L cos ( wt + \phi )

from this we get

q = qo e( - N\piR sqrt ( C/L))

____________________________

(a)

for N = 5

q = 6 e( - 5\pi* 7.2 sqrt ( 3.3e-6/12.1))

q = 5.655 uC

__________________

(b)

for N = 10

q = 5.332 uC

___________________

(c)

for N = 100

q = 1.8413 uC

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