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Chapter 31, Problem 024 GO Your answer is partially correct. Try again. A single-loop circuit consists of a 7.42 resistor, 11

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R = 7.4r, Lell. 9H, C= 3.3 M F = 3.3x100F 90 - 6.3 Mc (a) charge on capacitor after time t is q= Q e- tR/2L cos (utto) T= 20(a) do After 5 cycles that is N=5 q = 6.3 e - (5 50 X 7.4 53.3810641109) q = 5.93 uc ) (6) After N=10 a = 6.3 e-(10st (14) ✓

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