Question

A single-loop circuit consists of a 7.50 2 resistor, a 15.0 H inductor, and a 3.00 uF capacitor. Initially the capacitor has a charge of 6.70 PC and the current is zero. Calculate the charge on the capacitor N complete cycles later for N = 5. Submit Answer Tries 0/10 Calculate the charge on the capacitor N complete cycles later for N = 50. Submit Answer Tries 0/10 Calculate the charge on the capacitor N complete cycles later for N = 100.

Answer 1

The charge is, q=Qe 2 cos(@t+) Let "T" is the period Hence after "N" complete cycles, time is, t=NT q=Qe 22 cos(@NT +) But 7 2016 q=&e * cos( @v(27) +0) =pecos (20.1 +0) = Qe 22 cos(2N1+) = Qe RV/Z cosø But Qcoso is the initial charge q. a=9. a)For N=5 =(6.7x106)27756575, faze =6.356140897x10C =6.36 uc b) For N=50 9=9e2VIDEO = (6.7*10*) 775X50)=3 okto c = 3.956051x10 =3.96 uc

c) For N=100 q=%e*** = (6.7x106)247510), SMATC = 2.33587212x10C =2.34 uc