A converging lens (f1 = 24.0 cm) is located 56.0 cm to the left of a diverging lens (f2 = -28.0 cm). An object is placed to the left of the converging lens, and the final image produced by the two-lens combination lies 20.1 cm to the left of the diverging lens. How far is the object from the converging lens?
A converging lens (f1 = 24.0 cm) is located 56.0 cm to the left of a...
A converging lens (f1 = 12.4 cm) is located 28.8 cm to the left of a diverging lens (f2 = -6.36 cm). A postage stamp is placed 34.8 cm to the left of the converging lens. Locate the final image of the stamp relative to the diverging lens. answer in cm
1) A converging lens (f1 = 10.9 cm) is located 31.2 cm to the left of a diverging lens (f2 = -6.18 cm). A postage stamp is placed 32.4 cm to the left of the converging lens. Find the overall magnification. 2) An object is placed in front of a convex mirror, and the size of the image is one-fourth that of the object. What is the ratio (do/f) of the object distance to the focal length of the mirror?
A diverging lens (f1 = −11.5 cm) is located 43.0 cm to the left of a converging lens (f2 = 30.0 cm). A 4.0-cm-tall object stands to the left of the diverging lens, exactly at its focal point. Determine the distance of the final image relative to the converging lens.
10. A diverging lens (f1 = −10.5 cm) is located 52.0 cm to the left of a converging lens (f2 = 31.5 cm). A 2.5-cm-tall object stands to the left of the diverging lens, exactly at its focal point. Determine the distance of the final image relative to the converging lens.
A diverging lens (f1 = −14.0 cm) is located 25.0 cm to the left of a converging lens (f2 = 23.5 cm). A 4.0-cm-tall object stands to the left of the diverging lens, exactly at its focal point. What is the height of the final image (including proper algebraic sign)?
A diverging lens (f1 = −11.0 cm) is located 20.0 cm to the left of a converging lens (f2 = 32.5 cm). A 4.0-cm-tall object stands to the left of the diverging lens, exactly at its focal point. What is the height of the final image (including proper algebraic sign)?
A diverging lens (f1 = −11.5 cm) is located 25.0 cm to the left of a converging lens (f2 = 34.0 cm). A 2.0-cm-tall object stands to the left of the diverging lens, exactly at its focal point. What is the height of the final image (including proper algebraic sign)?
7. A diverging lens (f1 = -10.5 cm) is located 20.0 cm to the left of a converging lens (f2 = 34.0 cm). A 3.5-cm-tall object stands to the left of the diverging lens, exactly at its focal point. What is the height of the final image (including proper algebraic sign)? cm
A converging lens with a focal length of 6.0 cm is located 24.0 cm to the left of a diverging lens having a focal length of -13.0 cm. If an object is located 11.0 cm to the left of the converging lens, locate and describ completely the final image formed by the diverging lens. Where is the image located as measured from the diverging lens? 63.81 cm Submit Answer Incorrect. Tries 3/10 Previous Tries What is the magnification? Submit Answer...
part 1: A converging lens (f = 10.8 cm) is located 32.0 cm to the left of a diverging lens (f = -7.80 cm). A postage stamp is placed 43.9 cm to the left of the converging lens. (a) Locate the final image of the stamp relative to the diverging lens. (b) Find the overall magnification. part 2: Two identical diverging lenses are separated by 16 cm. The focal length of each lens is -5.1 cm. An object is located...