Question

if the statue contains one seventh of original carbon-14 content how old is it? h=5700 hit A=Ao2^t/h

Answer 1

منرا know, the half life fermula is, ACHE AO () x/n where, AC+ - Amount of substance remaining after timet Ao=A(o)= Initial camount Initial camount of substance. time Poss elapsed. h- half life of substance t Here, h=5700, Act) AO, To find t. 7 So, we have, a Act) = A ( ₃ ) 1/4 AL t/5700 =) Ho ** =) t/5700 th ( =) 4 (+) = m(+)?sta (no te -1.9459102 = true In () I too ln (3) (imab=bena In on both sides 2) =) t = (-1.945910)(5700) -6-693147 =) t 16001.925 [ 16002 .'. After laer 18002 yaa unit time the curhunth content of Statue will be be one seventh of original carbon - 14