Some fossil bones containing 1/32 of their original amount of carbon-14 are found. How many half-lives have passed? How old are the bones? (HINT: The half-life of carbon-14 is 5,730 years. If 1/8 of the original amount of carbon-14 was present, 1/8 = 1/23 or 1/(2x2x2), therefore 3 half-lives would have passed and therefore, the bones would be 5,730 years x 3 = 17,190 years old)
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Some fossil bones containing 1/32 of their original amount of carbon-14 are found. How many half-lives...
1. An archaeologist conducting a dig in New Mexico discovers some ancient bones. radiocarbon analysis indicates that 0.249 of the original amount of carbon-14 is left a. approximately how many half-lives have elapsed/passed b.if the single half-life value for carbon-14 is 5730 years, approximately how old are the remains?
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Carbon-14 is a radioactive isotope of carbon with a nucleus containing 6 protons and 8 neutrons. Its presence in organic materials is the basis of the radiocarbon dating. The half-life of carbon-14 is 5,730 years. If a fossilised tree trunk originally contained 8 nanograms of C-14, how long will it take for the C-14 to decay to 1 nanogram
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Carbon-14 has a half-life of 5730 years. In a plant fossil, you find that the C has decayed to 1/320 of the oniginal amount. How long ago was this plant alive? Express your answer numerically in years. View Available Hint(s) years
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