The amount of carbon-14 present in animal bones t years after the animal's death is given...
The amount of carbon-14 present in animal bones after t years is given by P(t) = Poe -0.00012! A bone has lost 36% of its carbon-14. How old is the bone? The bone is years old. (Round to the nearest integer as needed.)
Rewrite the following as an equivalent expression with rational exponents. .yzo (Simplify your answer.) The amount of carbon-14 present in animal bones after t years is given by P(t) =Poe -0.000120071 A bone has lost 32% of its carbon-14. How old is the bone To the nearest year, what is the age of the bone? (Round to the nearest integer as needed.)
The radioactive element carbon-14 has a half-life of 5750 years. A scientist determined that the bones from a mastodon had lost 53.2% of their carbon-14. How old were the bones at the time they were discovered? The bones were about years old. (Round to the nearest integer as needed.)
Suppose an Egyptian mummy is discovered in which the amount of carbon-14 present is only about - the amount found in living human beings. The amount of carbon-14 present in animal bones after t years is given by y, where is the amount of carbon-14 present in living human beings. About how long ago did the Egyptian die?
The radioactive element carbon 14 has a hall of 5750 years. A scientist determined that the bones from a mastodon had lost 70.8% of their carbon14. How old were the bones at the time they were discovered The bones were about years old (Round to the nearest Integer as needed
Question Help n The radioactive element carbon-14 has a half-life of 5750 years. A scientist determined that the bones from a mastodon had lost 64.5% of their carbon-14. How old were the bones at the time they were discovered? The bones were about years old. (Round to the nearest Integer as needed.) ina
Some fossil bones containing 1/32 of their original amount of carbon-14 are found. How many half-lives have passed? How old are the bones? (HINT: The half-life of carbon-14 is 5,730 years. If 1/8 of the original amount of carbon-14 was present, 1/8 = 1/23 or 1/(2x2x2), therefore 3 half-lives would have passed and therefore, the bones would be 5,730 years x 3 = 17,190 years old)
5.6.vQ-3 Question Help Watch the video and then solve the problem given below. A scientist determined that the bones from a mastodon had lost 75.5% of their carbon-14. How old were the bones at the time they were discovered? The bones were about years old. Round to the nearest integer as needed.)
This Question: 1 pt 17 of 31 (28 complete) is Quiz: 31 pts possi Suppose an Egyptian mummy is discovered in which the amount of carbon-14 present is only about three-fourths the amount found in living human beings. The amount of carbon 14 present in animal bones after t years is given by y = yo c -0.00012161 where yo is the amount of carbon-14 present in living human beings About how long ago did the Egyptian die? About yr...
An artifact originally had 16 grams of carbon-14 present. The decay model A = 16 e -0.000121t describes the amount of carbon-14 present after t years. Use the model to determine how many grams of carbon-14 will be present in 7367 years. The amount of carbon-14 present in 7367 years will be approximately N grams. (Round to the nearest whole number.)