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The amount of carbon-14 present in animal bones after t years is given by P(t) = Poe -0.00012! A bone has lost 36% of its car

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Plt) - -0.00012 t Po e Bone Lost 367. of carbon. 36%. 647 Carbon loor. left P(A) = 0.64 Po 0.00012 + La 0.64 Po Po e 0.00012

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