Question

Q2 [20 pts]: Imagine that you have two identical perfect linear polarizers. Place them one behind the other and position their transmission axes at 20° and 70°, respectively. If a linearly polarized beam of light with its electric field at 40° enters the first polarizer, how much light will emerge from the second polarizer?

Answer 1

Solution The angle blw the transmission axes of first lineor polariser and vertical oxel 0, = 20 linear polariser angle blo the transmission axes of second and vertical axes is O2 = 70° linear श्र The angle blw the transmission axes of third polariser and vertical axes is 03 = 409 Let, the irradiance the incident natural light be I. The function a linear polariser is to divide of natural light equally So, for the first polariser, the irradiance natural light would become a the iradiance Il I 2 As per Question, The angle blew the transmission axes g the frost and second polariser is Od 709 - 20° 500 Oz 0 - d

is obtained Il I Accordi ng to Malue Low, the irradiance of eight that would come out from the second polarizer by expression mathematics mathematically, Il 0d) cos? (0d) Substitute the value I, and Od I, cos? (od I cos? (500) 2 Iz = When the third polasizer is inserted blo first and second polarizer; the a angle first and third polarizer 2 - 0.206 I w/cm² حیاط Odi Oz-o 40° -20° Od 20° Again as per Maleys Low; I (Ode) - 13 - I, cos? (0) I Iz Cos%4200) I3 = 0.441 I w/cm2 Similarly, angle blow third polarizes and second polarizer Odz Oz-₂ 40 – 70° - 30° Odz

Abbying Malus law, the isradiation of light that would come out from the Second polarizer is obtained as - Id 13 2012) 0.44I I ws? (-300) 0.441 I X 0.75 0.330 I WICM Los I a - w/cm