Question

show work please!!!

spoents A 44 mH inductor, a 6.9 pF capacitor, and a 73 O resistor are placed in series. A signal generator is placed across them that has a frequency of iss Hz. If the RMS voltage across the resistor is 34V What is the signal generator's RMS voltage?

Answer 1

The current in the series circuit is voltage across resistor divided by resistance

The rms voltage of the generator is current times impedance of the circuit. The impedance is

$Z=\sqrt{\left(2 \pi f L-\frac{1}{2 \pi fC}\right)^2+R^2}$

given L = 44 mH = 0.044 H

f = 158 Hz

C= 6.9 x 10^-6 F

$Z=\sqrt{\left(2\pi \times 158\times 0.044-\frac{1}{2\pi\times 158\times 6.9\times 10^{-6}}\right )^2}=125.68\,\Omega$

or

Therefore the rms voltage of generator is  

$V=IZ=0.466\times 125.68=58.5\,V$