Question

Implement the following function in the PyDev module functions.py and test it from a PyDev module named t15.py: def matrix_equal (matrixi, matrix2): i.e. have the Compares two matrices to see if they are equal same contents in the same locations. Use: equal matrix_equal (matrix1, matrix2) Parameters: matrix1 the first matrix (2D list of ?) matrix2 the second matrix (2D list of ?) Returns: equal True if matrix and matrix2 are equal, False otherwise (boolean) NMN Sample testing First matrix: 0 0 d 2 b i 1 0909 + N Second matrix: 0 0 a 1 C d b 09 09 N 2 Equal matrices: True

Answer 1

#source code:

def matrix_equal(matrix1,matrix2):

for i in range(len(matrix1)):

for j in range(len(matrix1[i])):

if(matrix1[i][j]!=matrix2[i][j]):

return False

return True

mat1=[['c','a','t'],['d','o','g'],['b','i','g']]

mat2=[['c','a','t'],['d','o','g'],['b','i','g']]

status=matrix_equal(mat1,mat2)

print("First matrix:")

for i in range(len(mat1)):

for j in range(len(mat1[i])):

print(mat1[i][j],end="\t")

print("\n")

print("Second matrix:")

for i in range(len(mat1)):

for j in range(len(mat1[i])):

print(mat2[i][j],end="\t")

print("\n")

print("Equal matrices:",status)

1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 def matrix_equal(matrixi, matrix2): for i in range(len(matrix1)): for j in range(len(matrixl[i])): if(matrixl[i][j]!=matrix2[i][j]): return false return True mat1=[['c', 'a','t'],['d','o','g'],['b','i','g']] mat2=[['c', 'a','t'],['d', 'o','g'1,['b', 'i','g'll status=matrix_equal (mati,mat2) print("First matrix:") for i in range(len (matí)): for j in range(len(matl[i])): print(mati[i][j], end="\t") print("\n") print("Second matrix:") for i in range(len(matí)): for j in range(len(matl[i])): print(mat2[i][j], end="\t") print("\n") print("Equal matrices:", status) 22

#output:

user@user-Latitude - 3490:-/Desktops python3.7 1.py First matrix: c t a t d o g b i g Second matrix: C a t d o g b i g Equal matrices: True user@user-Latitude - 3490:-/Desktop$ I