Consider the function f(x) = 2x 123? slope of the function on this interval. 72c +...
Consider the function f(x)=2x^3−3x^2−72x+6 on the interval [−5,7]. Find the average or mean slope of the function on this interval. Average slope: 0 By the Mean Value Theorem, we know there exists at least one value cc in the open interval (−5,7) such that f′(c) is equal to this mean slope. List all values cc that work. If there are none, enter none . Values of c:
(1 point) Consider the function f(x) = on the interval [4,9]. Find the average or mean slope of the function on this interval. By the Mean Value Theorem, we know there exists a c in the open interval (4,9) such that f'(c) is equal to this mean slope. For this problem, there is only one c that works. Find it.
(1 point) Let f(x) = xvx + 6. Answer the following questions. 1. Find the average slope of the function f on the interval [-6,0). Average Slope: m= 2. Verify teh Mean Value Theorem by finding a number c in (-6,0) such that '(c) = m. Answer: m20-mingla-0165 / application_-_mean_value_theorem / 2 Application - Mean Value Theorem: Problem 2 Next Problem Previous Problem Problem List (1 point) Consider the function f(x) = x2 - 4x + 9 on the interval...
Consider the function on the interval (0, 2). f(x) = sin(x) cos(x) + 8 (a) Find the open interval(s) on which the function is increasing or decreasing. (Enter your answers using interval notation.) increasing decreasing (b) Apply the First Derivative Test to identify all relative extrema. relative maxima (x, y) = (smaller x-value) (larger x-value) (X,Y)= (x, y) = (1 (x, y) = relative minima (smaller x-value) (larger x-value)
can you do part 4 & 5 for me 4. How do we define the average value of the function f(x) on the interval [a, b]? (see page 461 of the text) favg 5. Complete the Mean Value Theorem for Integrals on page 462 of the text. If f is continuous on [a, b], then there exists a number c in [a, b] such that f(c)- that is 4. How do we define the average value of the function f(x)...
Find any values of cwhere the function f(0) = 2x² + 3x – 4satisfies the conclusion of the Mean Value Theorem on the interval (0,3).
Let us verify the Mean Value Theorem with the function f(x) = VE on the interval (2,8). Solution. We have f is continuous on (2,8) f is differentiable on (2,8). f'(o) – f(8) – f(2) 8 - 2 We have f'(x) = The only value that satisfies the Mean Value Theorem is
(1 point) Consider the function f(x) = x2 - 4x + 2 on the interval [0,4]. Verify that this function satisfies the three hypotheses of Rolle's Theorem on the inverval. on f(x) is on [0, 4); f(x) is (0, 4); and f(0) = f(4) = Then by Rolle's theorem, there exists at least one value c such that f'(c) = 0. Find all such values c and enter them as a comma-separated list. Values of се (1 point) Given f(x)...
Consider the function f(x) = 2x + 6x2 - 144x + 6. For the following questions, write inf for 0, -inf for --O, U for the union symbol, and NA (ie. not applicable) if no such answer exists. a.) f'(x) = 6x^2+12X-144 b.) f(x) is increasing on the interval(s) c.) f(x) is decreasing on the interval(s) d.)f(x) has a local minimum at NA e.)f(x) has a local maximum at NA f.)f"(x) = 12x+12 g.)f(x) is concave up on the interval(s)...
help Spt 7. Verify that the function f(x) = Vr+1 satisfies the hypotheses of the Mean Value Theorem on the interval (0,3). Then find all numbers c that satisfy the conclusion of the Mean Value Theorem. pt 8. Find the absolute maximum and absolute minimum values of the function f(x)- In(4r2 +2r+1) on the interval -1,0). Spt 7. Verify that the function f(x) = Vr+1 satisfies the hypotheses of the Mean Value Theorem on the interval (0,3). Then find all...