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8. (2 pts) Use the tabulated half-cell potentials to calculate AGⓇ for the following balanced redox...
Use the tabulated half-cell potentials to calculate ΔG° for the following balanced redox reaction. (F = 96,485 C/mol e) 2Li( s) + Cl 2 ( g) → 2 Cl - ( aq) + 2Li +( aq) Eº Li+(aq) + e- → Li(s) -3.04V Cl2 (g) + 2e- → 2 Cl- (aq) +1.36 V a. -425 kJ b. -849 kJ c. -8.49 x 10 5 kJ d. +324 kJ
25) Use the tabulated half-cell potentials to calculate the equilibrium constant (K) for the following balanced redox reaction at 25°C. 2 Al(s)+3 Mg2+(aq) A) 1.1 x 1072 B) 8.9 x 10-73 C) 1.1 x 10-72 D) 1.0 x 1024 E) 4.6 x 1031 2 Al3+(aq) +3 Mg(s)
Use the tabulated half-cell potentials to calculate AG for the following balanced redox reaction 312(s) + 2 Fe(s) -- 2 Fe3+ (aq) + 6 (aq) HO MH MBS MOHO HO 2 Olet M2 2TH 2 HOU M2H00 bado 120 1.00 . VOL 2 NO, & COM Agla Feate 2 Hal. 20 Mno, lagi + le Qu'll A2H0+48 +2 SO/' tal + 4H+ 2 VOHO NO 2o CO Ag felag Ho MO 21 07 ON 0.40 0.34 Cuis H, SOHO Culagi...
Use the tabulated half-cell potentials to calculate AGº for the following balanced redox reaction 3 12(s) + 2 Fe(s) → 2 Fe3+(aq) + 6 H(aq) +23 x 102 kJ 0 +49 x 101 kJ -1.1 x 102 kJ 0 -9.7 x 101 kJ 0 -3.3 x 102 kJ
A) Use tabulated electrode potentials to calculate ΔG∘ for the reaction. 2K(s)+2H2O(l)→H2(g)+2OH−(aq)+2K+(aq) B) (Refer to the following standard reduction half-cell potentials at 25∘C: VO2+(aq)+Ni2+(aq)2H+(aq)++2e−e−→ →Ni(s)VO2+(aq) +H2O(l)E∘=−0.23V E∘=0.99V) An electrochemical cell is based on these two half-reactions: Oxidation:Reduction:Ni(s)VO2+(aq,0.024M)+2H+(aq,1.4M)+e−→→Ni2+(aq,1.8M)+2e−VO2+(aq,1.8M)+H2O(l) Calculate the cell potential under these nonstandard concentrations. C) Standard reduction half-cell potentials at 25∘C Half-reaction E∘ (V ) Half-reaction E∘ (V ) Au3+(aq)+3e−→Au(s) 1.50 Fe2+(aq)+2e−→Fe(s) − 0.45 Ag+(aq)+e−→Ag(s) 0.80 Cr3+(aq)+e−→Cr2+(aq) − 0.50 Fe3+(aq)+3e−→Fe2+(aq) 0.77 Cr3+(aq)+3e−→Cr(s) − 0.73 Cu+(aq)+e−→Cu(s) 0.52 Zn2+(aq)+2e−→Zn(s) − 0.76...
30) Use the tabulated half-cell potentials below to calculate the equilibrium constant (K) for the following balanced redox reaction at 25°C. Pb2+(aq) + Cu(s) → Pb(s) + Cu2+(aq) Pb2+(aq) + 2e → Pb(s) Cu2+ (aq) +2e → Cu(s) E° = -0.13 V E = 0.34 V C) 7.9 x 1015 A) 7.9 x 10-8 D) 1.3 x 10-16 B) 8.9 x 107 E) 1.1 x 10-8
Use the tabulated electrode potentials to calculate K for the oxidation of nickel by H+: Ni(s)+2H+(aq)→Ni2+(aq)+H2(g) Express your answer using two significant figures. Standard reduction half-cell potentials at 25∘C Half-reaction E∘ (V) Half-reaction E∘ (V) Au3+(aq)+3e−→Au(s) 1.50 Fe2+(aq)+2e−→Fe(s) −0.45 Ag+(aq)+e−→Ag(s) 0.80 Cr3+(aq)+e−→Cr2+(aq) −0.50 Fe3+(aq)+3e−→Fe2+(aq) 0.77 Cr3+(aq)+3e−→Cr(s) −0.73 Cu+(aq)+e−→Cu(s) 0.52 Zn2+(aq)+2e−→Zn(s) −0.76 Cu2+(aq)+2e−→Cu(s) 0.34 Mn2+(aq)+2e−→Mn(s) −1.18 2H+(aq)+2e−→H2(g) 0.00 Al3+(aq)+3e−→Al(s) −1.66 Fe3+(aq)+3e−→Fe(s) −0.036 Mg2+(aq)+2e−→Mg(s) −2.37 Pb2+(aq)+2e−→Pb(s) −0.13 Na+(aq)+e−→Na(s) −2.71 Sn2+(aq)+2e−→Sn(s) −0.14 Ca2+(aq)+2e−→Ca(s) −2.76 Ni2+(aq)+2e−→Ni(s) −0.23 Ba2+(aq)+2e−→Ba(s) −2.90 Co2+(aq)+2e−→Co(s) −0.28 K+(aq)+e−→K(s) −2.92 Cd2+(aq)+2e−→Cd(s)...
Use the tabulated half-cell potentials below to calculate AG ( in Kilojoules for the following balanced redox reaction. F= 96,500 J/. mole e Pb2+(aq) + Cu(s) - Pb(s) + Cu2+(aq) Cu2+ (aq) + 2e -> Cu(s) E". Cu = -0.34 Volt Pb2+ (aq) + 2e-> Pb(s) E,Pb = -0.13 volt a. -41 kJ b. -81 kJ C. +46 kJ d. +91 kl e..91 kb 24 Calculate AS®rxn for the following reaction. The S' for each species is shown below the...
1. Use the tabulated half-cell potentials to calculate AG for the following balanced redox reaction. SHow your work 2 Fe3+(aq) + 6 1(aq) 3 12(s)+ 2 Fe(s)
Use the tabulated half-cell potentials to calculate the equilibrium constant (K) for the following balanced redox reaction at 25°C. 3 I2(s) + 2 Fe(s) → 2 Fe3+(aq) + 6 I(aq) A.8.9 × 10-18 B.1.1 × 1017 C.1.7 × 1029 D.2.4 × 1058 E.3.5 × 10-59