Suppose that $11,399 is invested at an interest rate of 6 3% per year, compounded continuously...
Suppose that $18,961 is invested at an interest rate of 5.7% per year, compounded continuously. a) Find the exponential function that describes the amount in the account after time t, in years. b) What is the balance after 1 year? 2 years? 5 years? 10 years? c) What is the doubling time? a) The exponential growth function is P(t)= (Type exponential notation with positive exponents. Do not simplify. Use integers or decimals for any numbers b) The balance after 1...
Suppose that $16,416 is invested at an interest rate of 5.5% per year, compounded continuously. a) Find the exponential function that describes the amount in the account after time t, in years. b) What is the balance after 1 year? 2 years? 5 years? 10 years? c) What is the doubling time? a) The exponential growth function is P(t) = (Type exponential notation with positive exponents. Do not simplify. Use integers or decimals for any
1) Please write clearly. Suppose that $12,170 is invested at an interest rate of 5.1% per year, compounded continuously. a) Find the exponential function that describes the amount in the account after time t, in years. b) What is the balance after 1 year? 2 years? 5 years? 10 years? c) What is the doubling time? a) The exponential growth function is P(t) = 0. (Type exponential notation with positive exponents. Do not simplify. Use integers or decimals for any...
In 2012, the population of a city was 5.82 million. The exponential growth rate was 2.28% per year. a) Find the exponential growth function. b) Estimate the population of the city in 2018. c) When will the population of the city be 8 million? d) Find the doubling time. a) The exponential growth function is P(t) = , where t is in terms of the number of years since 2012 and P(t) is the population in millions. (Type exponential notation...
Suppose $6,600 is invested at interest rate k, compounded continuously, and grows to $10,600 in 6 years. a) Find the interest rate. b) Find the exponential growth function. c) Find the balance after 10 years.
Suppose that is invested in a savings account in which interest, k, is compounded continuously at 3% per year. The balance P(t) after time t, in years, is P(t) = Pekt a) What is the exponential growth function in terms of P and 0.03? P(t)=0
the population of a city was 5 45 million. The exponential growth rate was 2 64% per year. a Find the exponential growth function b Estimate the population of the city in 2018 c) When will the population of the city be 7 million? d) Find the doubling time. a) The exponential growth function is P(t)# where t is in terms of the number of years since 2012 and Type exponential notation with positive exponents Do not simplity Use integers...
1) Please write clearly. In 2012, the population of a city was 5.97 million. The exponential growth rate was 1.66% per year. a) Find the exponential growth function. b) Estimate the population of the city in 2018. c) When will the population of the city be 10 million? d) Find the doubling time. a) The exponential growth function is P(t) = 1, where t is in terms of the number of years since 2012 and P(t) is the population in...
5) Suppose $6,600 is invested at interest rate k, compounded continuously, and grows to $10,600 in 6 years. a) Find the interest rate. b) Find the exponential growth function. c) Find the balance after 10 years.
How much will $100 grow to if invested at a continuously compounded interest rate of 7.75% for 9 years? (Do not round intermediate calculations. Round your answer to 2 decimal places.) How much will $100 grow to if invested at a continuously compounded interest rate of 9% for 7.75 years? (Do not round intermediate calculations. Round your answer to 2 decimal places.)