The volume of the triangular
block is 4 cubic inches.
What is the approximate length of y? Round to the nearest tenth of an inch.
1.4 in.
2.0 in.
2.8 in.
3.5 in.
Volume of box is (x*x*x/2)=4
= x^3=8
X=2.
Now the relationship between x and y , by pythagoras
X^2+x^2=y^2
Y^2= 2*(x)^2
Y^2= 2×2^2
Y^2= 8
Y=2√2
Y approximately equal to 3 inch.
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