Question

2) Assume the small end of the part shown below has a basic bore diameter of 0.25 Inches. We want to assemble the part with a pin with a basic shaft diameter of 0.25 inches, ensuring that the fit between the two parts is a running fit. If we determine that the optimal clearance between the two parts is 0.0009", but no larger than 0.0017", what Class fit would you specify on the drawing? Also calculate the minimum and maximum clearance allowed for this fit class. See Appendix A-1 (25 pts) Class MMC LMC Hole Minimum Clearance Shaft Maximum Clearance f Appendix A: Limits and Fits ) A. 1) LIMITS AND FITS (INCH) A. 1.1) Running or sliding clearance fits Basic hole system. Limits are in thousandths of an inch. Limits for hole and shat are applied algebraically to the basic size to obtain the limits of size for the parts Class tandard Limits RC3 Class RC Standard Limits s Standard Liits Shaft Shaf +0.25-0.1 Shaft -0.3 Hole 0.3 -0.7 0.5570.4 +0.6 0.12+0.2 +0.4 0.12 ー0.24| +0.2 1415 T +0.3 -1.0.15 1 +0.5 0.350+0.9 0.2 -0.4 .0.7 -0.9 -0.5 0.24 0.40 +0.25-0.2 +0.4 0.400.71 0.3 0.25 +0.4 0.25 +0.7 0.711.19+0.40.3 +0.6 0.35 0.9 0.6 -0.6 0.45 0.55 -0.3+0.5 0.3 +0.8 0.8 -0.8 .191.97 +0.4-0.4 +0.6 -0.4 0,7 0.7 .97 -3.15 +0.504 2.0 1.60 0.74 1.2 3.15-4.73+0.6 473-709 07 7.09 -9.850. 85 12410.9 41-15.751.0 2.4 0.5 0.9 +0.9 +2.2 -2.3 0 +2.5 -3.2 +2.8 2.0 3.8 2.2 +1.2-0.7 +2.0 0 0 0 0 2.5 +3.0 +3.5 +4.0 -0.7 +2.2 -4 -2.5 2.0 +2.5 2.8

Answer 1

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