Question

A system of two converging lenses forms an image of an arrow as shown. The first lens is located at x and has a focal Length off, = 9.5 cm. The second lens is located at x = x2 = 52 cm and has a focal length of fx = 17.9 cm. The tip of the object arrow is located at (x,y) = x,y) (-14.2 cm, 3 cm). 1) What is x1, the x co-ordinate of image of the arrow formed by the first lens? cm Submit 2) What is y1, the y co-ordinate of the image of the tip of the arrow formed by the first lens? cm Submit 3) What is x3, the x co-ordinate of image of the arrow formed by the two lens system? Submit + 4) What is y3, the y co-ordinate of the image of the tip of the arrow formed by the two lens system? cm Submit 5) What is the nature of the final image relative to the object? O Real and Inverted Real and Upright O Virtual and Inverted Virtual and Upright Submis 6) Which of the following changes to the locations of the lenses would result in a virtual and inverted image of the original object arrow? Move the first lens to x = -9.45 cm, keeping the second lens at x = 52 cm. Move the second lens to x = 60.95 cm, keeping the first lens at x = 0. Move the second lens to x = 37.6521276595745 cm, keeping the first lens at x = 0. None of the above moves will produce a virtual inverted image of the object arrow. Submit

Answer 1

(1) Using lens ㅗ fi equation t + 1 dil doi = T = ㅗ 21, 44.2 9.5 -) 21, 28.7cm (2) Magnification = -dil dou chi ho -) 28. ih 14.2 • 2 ६ -G.06 cm ) yi bugn (E) lens equation - T T = T 17-9 1 t1 fi dir doz I dir (52-28.7) - die = 77.235 cm 52 +77.235 129.235 cm .5cm Y3F - 77.235 (52 -28.7) - 20.o 9 cm (5) Real and upright .: 203 41 X (-6.06)

Answer 2

Answer

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