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QUESTION 2 T(n) = Tỉn/2) + n T(n) = "Theta" QUESTION 3 T(n) = 2 Tỉn/2)...
def plusThetaeigenket(theta): return np.array([np.cos(theta/2),np.sin(theta/2)]) print("|+theta> = ",plusThetaeigenket,"\n") def minusThetaeigenket(theta): return np.array([-np.sin(theta/2),np.cos(theta/2)]) print("|-theta> = ",minusThetaeigenket,"\n") Can you please help to solve where this python code went wrong for display the correct eigen ket value for theta? Thank you |<+y|-y>l^2 = 0.9999999999999996 ||<+y|-x>l^2 = 0.4999999999999998 -4 print("*Exercise 30.5\n"), -5 #function defination for plus and minus theta eigenkets -6 def plusThetaeigenket(theta): +7 return np.array([np.cos(theta/2), np.sin(theta/2)]), -8 print("[+theta> = ",plusThetaeigenket,"\n"), *Exercise 30.5 -9 +theta> = <function plus Thetaeigenket at Ox00000160BCO9CD08> o def minus Thetaeigenket(theta):...
Please help me to solve this Algorithm question Show that 3n^3 +/2 - 17 = theta(n^3) Show that 2n^3 + 1 notequalto 0(n^2)
Does theta(n^3+2n+1) = theta(n^3) hold? Justify your answer.
Show the recursion tree for T(n) = 4T(n/4) + c and derive the solution using big-Theta notation. Explain the intuition why this result is different from the solution of T(n) = 4T(n/2) + c.
if n < 8 T(n) 11([n/2]) +T([n/4]) +T([n/8]) +n otherwise Use the substitution method, obtain a Big-Theta bound for T(n). [We expect a rigorous proof. You don't need to explain how you managed to guess the upper and lower bounds.
Given algorithm A(n): A(n): { A(n/4); for i = 1 ton sum++; A(n/4); } Fill in the appropriate expressions in the box provided: T(n) = TO ) + 问题6 T(n) = 4 Tên/3) + n T(n) = "Theta" 2:57 T(n) = 2 Tn/2) + 1 T(n) = "Theta" 098 T(n) = T/n/2) + n T(n) = "Theta" 问题9 T(n) = 3 Tn2) + n T(n) = "Theta"
given the following recurrence find the growth rate of t(n) using master theorem T(n) = 16(T) n/2 + 8n^4 + 5n^3 + 3n+ 24 with T(1) = Theta(1)
Prove that Theta(n) +O (n^2) notequalto O(n^2)
Discrete Math Give a big-Theta estimate for the number of additions in the following algorithm a) procedure f (n: integer) bar = 0; for i = 1 to n^3 for j = 1 to n^2 bar = bar + i + j return bar b) Consider the procedure T given below. procedure T (n: positive integer) if n = 1 return 2 for i = 1 to n^3 x = x + x + x return T(/4) + T(/4) +...
What is the theta of the following summation: 1^3 + 2^3 + 3^3+ ... +i^3+ ... + N^3