3. Provide a mechanism for the following reaction. (This a hint to question 2) 5 points...

Question

Question

Answer 1

Answer #1

In the first reaction after leaving iodide the tertiary carbocation will form.

The formed tertiary carbocation changes into more stable allylic tertiary carbocation by hydrogen migration.

Finally the water molecule attack the finaly formed tertiary carbocation which gives our product.

ED Hyclegor - migration H H 왕 HD,

The second reaction is an example of E1-Elimination. The tertiary bromide react with NaOH give alkene as the product.

BY OH 7H Nauon got nombouwd3-15

Answer 2

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