Question

Calculate the moments of inertia (I_x and Iy) for the steel plate shown below:

r= 50 mm 150 mm 150 mm 400 mm 400 mm 150 mm 150 mm

Answer 1

Solue. 4000N 282.84 150 MM r=50NN do 100 NM = 0.16 0450 x 682/84 ( 1) x 400ml 2100 MM, 15ONN, 'y In the Ixx = ligucce as If Symmetrical 20 Tyy. So of use calculate Txx , Iyye can be known easily. (copper part) - Ixx chini) (T98 04+.xp? + apo (150)39 TAD? (4хr 37. TD4 64 Ixx 12 12 565.680282.843 (245489.26 4 12688.25 -( 4908738.62 + 176734586-8) Ixx = 1066625750 - 8445515.02 -181623925.3 Ixx 876556909.7 MM4 Cupper part)

of Should be equal Ixx of upper part to houler pault as both upper part and lowles pault are equal. So Ixx + (Ixx) joules 876556909.7 + 876556909.7. Ixx = 1753113819.1M4. . (Ixx) upper Section ok figure and as is previously written Synn nimetrical So Ixx = Iyy hence Iyy = 1753113819 MM44. So Ixx Iyy = 1753113819 MM4 = 1753113819 M114.