Question

Solve by using Python language

Validation of Invoice Number

The Gocargo carriers are extending their automation to their accounts wing too, It is difficult to identify the source and destination of a cargo in an invoice. So given an invoice number, determine the "from" and "to" for a cargo.

The format of invoice number is as follows:
* from-Country and to-Country are separated by few digits(atleast 1)
* after to-Country there are few digits.

Input Format :
      Input consists of a string, which corresponds to the invoice number of a cargo.

Output Format :
      Output is also a string that corresponds to the source and destination of the cargo.
      Print "Invalid Input", if the input does not follow the specified format of invoice number.

Refer sample output for formatting specifications:

Sample Input 1:
IND1234PAKI345
Sample Output 1:
IND to PAKI

Sample Input 2:
INDPAKI345
Sample Output 2:
Invalid Input

Answer 1

#Python Code:-

# method to check is the string contains digit or not
def is_int(s):
flag1=True
try:
int(s)
except ValueError:
flag1=False
return flag1

def main():
s=input("Enter the invoice number of a cargo : ")
n=len(s)
str1=''
str2=''
str3=''
str4=''
flag=1
for i in range(0,n):
if is_int(s[i])==True:
break
else:
str1+=s[i]
  
for j in range(i,n):
if is_int(s[j])==True:
str2+=s[j]
else:
break
  
for k in range(j,n):
if is_int(s[k])==True:
break
else:
str3+=s[k]
  
for l in range(k,n):
if is_int(s[l])==True:
str4+=s[l]
else:
flag=1
break
if len(str1)==0 or len(str2)==0 or len(str3)==0 or len(str4)==0 or flag==0:
print("Invalid Input")

else:
print(str1,"to",str3)
  
  
if __name__=="__main__":
main()
  
  
  
  

oc main.py 1 # method to check is the string contains digit or not 2- def is_int(s): 3 flag1=True 4. try: 5 int(s) 6 except ValueError: 7 flag1=False return flagi 9 10 def main(): 11 s=input("Enter the invoice number of a cargo : ") 12 n=len(s) 13 str1='' 14 str=' 15 str3=' 16 str4 17 flag=1 18 for i in range(0,n): if is_int(s[i])==True: 20 break 21 else: 22 str1+=s[i] 23 24 for j in range(i,n): 25 if is_int(s[j])==True: 26 str2+=S[j] else: 28 break 29 for k in range(j,n): 31 if is_int(s[k])==True: 32 break 33 else: 34 str3+=s[k] 19 27 ليبيا ليليا ليليا ليليا لليا

35 36 37 38 39 for 1 in range(k,n): if is_int(s[1])==True: str4+=s[1] else: flag=1 break if len(str1)==0 or len(str2)==0 or len(str3)==0 or len(str4)==0 or flag==0: print("Invalid Input") 40 41 42 43 44 45 46 47 48 49- if 50 else: print(str1, "to", str3) main name main() input Enter the invoice number of a cargo : IND1234PAKI345 IND to PAKI ...Program finished with exit code 0 Press ENTER to exit console. I

Output 2:-

input INDPAKI345 Enter the invoice number of a cargo : Invalid Input ... Program finished with exit code 0 Press ENTER to exit console. I

Answer 2

import sys

invoice_number=input()

From=""

To=""

count=0

check=0

for i in range(0,len(invoice_number),1):

  if(invoice_number[i]>='A' and invoice_number[i]<='Z'):

      From=From+invoice_number[i];

      count+=1

  else:

    break

for j in range(count,len(invoice_number),1):

 if(invoice_number[j]>='0' and invoice_number[j]<='9'):

    count+=1

    check+=1

 else:

    break

if(count==len(invoice_number)):

  print("Invalid Input")

  sys.exit()

check=0

for i in range(count,len(invoice_number),1):

 if(invoice_number[i]>='A' and invoice_number[i]<='Z'):

    To=To+invoice_number[i];

    count+=1

 else:

    break

if(count==len(invoice_number)):

  print("Invalid Input")

  sys.exit()

for j in range(count,len(invoice_number),1):

 if(invoice_number[j]>='0' and invoice_number[j]<='9'):

    count+=1

    check+=1

 else:

    break

print(From+" to "+To)