Question

1. Continue the sequence (write the next two terms) and find a general formula for the n-th term if possible 11 3 1 5 3 7 5'3'10'2'9'5'11" 2.1=2. Are you surprised? I can prove it. See below, please. Proof (1) Let a=b (2) Multiply both sides by a: a'rab (3) Add to both sides: a +a=q'+ab (4) Simplify: 2a*=a +ab (5) Subtract 2ab from both sides: 2a-2ab=a+ab-2ab (6) Simplify: 2a-2ab=a'-ab (7) Factor: 2(a'-ab)=1(a -ab) (8) Divide both sides by (a-ab): 2=1 Do you agree with me? No? Where did I go wrong? What step was incorrect? 3. Once upon a time there was a beautiful princess named 1. Two knights named n/m Tand m/n were deeply in love with her and wanted to marry her. The princess said she would marry the knight closest to her. Who was her groom n/m or m/n? 4. What is greater x'or x?

Answer 1

answer is attached.

sot < 4, 5, 6, 4, 1 there must be some estor. ich it is 3 7. n nt4. then 3 1 7 1 2 4 3 1 1 1 1 1 1 1 1 1 1 1 1 13 - wth term :n n+4. If there is no typo-ensor, I might be wrong Q2 both as n 1 I am not agreed from step 2 - a² = ab a²-abzo from step 7 & 2(a2-ab) = 1 (a²ab) reduced in 2=1 a²_ab But we can't divide both sides by . a²-abzo. Q.3. If man princes i will marry on and will be both and closest to princess. If myn, no is closest to 1 m n will be the If nim in is closest to 1, n will be Q.4. üf E (0,1)= x-2 < x-3; if X=1; 2-2-2-3 if x e(-o) x2 > x-3 and if x E (119) x ²X-3 groom. n the groom.

Thank you.