Question

Score: 0 of 1 pt 9 of 13 (10 complete) ic: X 6.3.91 A variable is normally distributed with mean 15 and standard deviation 4. a. Find the percentage of all possible values of the variable that lie between 5 and 17. b. Find the percentage of all possible values of the variable that are at least 13. c. Find the percentage of all possible values of the variable that are at most 7. Click here to view page 1 of the table of areas under the standard normal curve. Click here to view page 2 of the table of areas under the standard normal curve. %. a. The percentage of all possible values of the variable that lie between 5 and 17 is (Round to two decimal places as needed.) %. b. The percentage of all possible values of the variable that are at least 13 is (Round to two decimal places as needed.) % c. The percentage of all possible values of the variable that are at most 7 is (Round to two decimal places as needed.)

Answer 1

solution Giren! XNN (u, 62) M=155) as = 6-4 Tall (5) p(5<x< 17.) = = pls-1 17-15) ac-6c X-y 10 (CEEP(-2.5C ZC 0.5) PIZc0.5) - plz<-2.5) from table. Cola 0.69196- 0.0062) Sooslo = 0.68525 =0.6853 15 P(GCXC17) - 68.53% 20 6 25 The percentages of all possible values of the variables that lie between's and 17 is 68.53% prx213): 1-PCXB) =1 - p(xy 13-15) =l-plz<-05) from table =1-0.30854 = 0.69196 = 0.69) 6 4 30

The percentage = 69.15% of all possible values of the Variable that at least 1 is 69.15% 5 plus 57 = plus 7-15) = P(Z <-2) 101 from table. = 0.02275 = 0.0228 = 2.28% The percentages of all possi ssible values of the Variable that are at most 7 is 2.28% 15