Question

Python Language Only!!!!

Python Language Only!!!!

Python Language Only!!!!

Python 3 is used.

Write a Python statement that creates a two-dimensional list named values with 3 rows and 2 columns. Then write nested loops that get an integer value from the user for each element in the list. Then display the content of the list. Please see the outcome below:

Outcome run:

Enter the 1 element in the 1 row :1

Enter the 2 element in the 1 row :2

Enter the 1 element in the 2 row :3

Enter the 2 element in the 2 row :4

Enter the 1 element in the 3 row :5

Enter the 2 element in the 3 row :6

The content of the list is:

1 2

3 4

5 6

(Needs to look exactly like outcome for thumbs up)

Answer 1

• 'str()' method ensures the int converted to str to get concatenated with the message.
• since for loop iterates from 0 to 1 and 0 to 2, we have to print i+1 and j+1 for getting actual row count rather than list index.
• 'end = " "' in a print statement ensures that the automatic newline after each print statement is skipped and space is printed in that place.
• 'append()' method is for attending an element to a list.

Screenshot Of Code:

1 5 6 8- n = + # declare values as a list 2 values [] 3 # start a for loop to iterate through 3 rows 4- for i in range(3): # initialize a row[] (empty list) to save values of current row that user is entering row = [] 7 # start a for loop to iterate through 2 columns for j in range(2): 9 # get input from user and append the same to the end of current row 10 # format message using i and j to display current position of input 11 input('Enter the '+ str(+1) +' element in the str(i+1) row:') 12 row.append(n) 13 # after iteration of each row append the row (row[] to list values values.append(row) 15 # print message for final output 16 print("The content of the list is:") 17 #iterate through each row of list using a for loop 18 - for i in range(3): 19 # iterate through each column of list using a for loop 20 for j in range(2): 21 # print ith row jth column element end = skips new 22 # line after each print statement rather puts a space at the end 23 print(str(values[i][j]), end = " ") 24 # print a newline after each row iteration. 25 print() 14

Output:

Enter the 1 element in the 1 row:1 Enter the 2 element in the 1 row:2 Enter the 1 element in the 2 row:3 Enter the 2 element in the 2 row:4 Enter the 1 element in the 3 row:5 Enter the 2 element in the 3 row:6 The content of the list is: 1 2 34 5 6

Code to Copy:

# declare values as a list
values = []
# start a for loop to iterate through 3 rows
for i in range(3):
# initialize a row[] (empty list) to save values of current row that user is entering
row = []
# start a for loop to iterate through 2 columns
for j in range(2):
# get input from user and append the same to the end of current row
# format message using i and j to display current position of input
n = input('Enter the '+ str(j+1) +' element in the ' + str(i+1) + ' row:')
row.append(n)
# after iteration of each row append the row (row[]) to list values
values.append(row)
# print message for final output
print("The content of the list is:")
# iterate through each row of list using a for loop
for i in range(3):
# iterate through each column of list using a for loop
for j in range(2):
# print ith row jth column element end = " " skips new
# line after each print statement rather puts a space at the end
print(str(values[i][j]), end = " ")
# print a newline after each row iteration.
print()