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Ans :-
Fe3+ (aq) + ClO- (aq) -----------------> FeO42- (aq) + Cl- (aq) + H2O (l)
Reaction at anode :
Fe3+ (aq) + 4H2O (l) -----------------> FeO42- (aq) + 8H+ (aq) + 3e-
Adding 8OH- on both sides, in order to convert this equation into basic medium :
Fe3+ (aq) + 8OH- -----------------> FeO42- (aq) + 4H2O (l) + 3e- .................(1)
Reaction at cathode :
ClO- (aq) + 2H+ + 2e- -----------------> Cl- (aq) + H2O (l)
Adding 2OH- on both sides, in order to convert this equation into basic medium :
ClO- (aq) + H2O (l) + 2e- -----------------> Cl- (aq) + 2OH- .................(2)
Add equations (1) and (2) after multiply equation (1) by 2 and equation (2) by 3, the balanced chemical equation in basic medium is :
| 2Fe3+ (aq) + 3ClO- (aq) + 10OH- ----> 2FeO42- (aq) + 5H2O (l) + 3Cl- (aq) |
Oxidation of transition metal is +6.
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When you write the answers, please write the page number for
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