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Two balls A and Ceach have a mass of m are moving to strike ball B which is at rest as shown in figure. If ball C strikes bal
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for first collision, Initial velocity of c,,Ylit SM/ste of VBĚ = 0 miste initial velocity B, final velocity of c. Nef= 2... BVBF = 5 - Ver VBF= i 0.375 Misce for second collision. Noi = 0.375 m/sec. VBF = VAN 3 m/schron Af = tv- Momentum conservationfrom equation ♡ ♡ - 2.625 VB + VA 20868 addition, VBH & VBF = NBF 00243) NBF = 001215 Mice This is the final Velocity of B af

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