Question

Two smooth billiard balls A and B each have a mass of 200 g. A strikes B with a velocity (VA)1 = 1.5 m/s as shown. Ball B is originally at rest and the coefficient of restitution is e = 0.85. Neglect the size of each ball. (Figure 1). Figure < 1 of 1 > 400 X

Answer 1

apply conservation of linear momentum, (5) MACARA MEUB= MACA2) & (MB) CBR) of (0-2x1.5c0348346.2%) = 02 QAz)2 +0.2008), Cheat Crazla=-1.25 -0 . 43 ė = WA2)ą-legea la 280a-fedra 0.85= VA2), (492) oc-15 cos40) Vaz) q=0.9775+82]a @ Gromno & © we get 2082)me = -1064 mys. VAZ) = -0.086 m/s. final velocity in vertical direction are the same as initial vestê cal velocities, С+) mA (+) у = ппд ( у воду Waz)y = Washy 45 =-115 singo = -0.964 m/s (47) MolB)y = mBQB2), @Boy = Qody zo Scanned with CamScanner

VA2 = Juara +8A 2 ) } (-0.0862)+60.964102 =0.9678ms 19 B2 = 108/2 thea = SE116069) +02 711064 mis a velocaties just after collision are VB2 = 1.064 m/s ] NA2 = 0.9678 m/s , Balls makes angle with horizontal, - tań (-0.9641) So, 284-90 ( --0-086 Ball makes an angle with vestical is (0y=0 / CScanned with CamScanner