Solve the following using the 5-step process If a projectile is launched upward with an initial...
At moment of time t=0 a projectile is fired directly upward with an initial velocity 192 ft/sec, and initial height 200 ft. Find: a)velocity and acceleration after t seconds, (b) velocity when projectile hits the ground, (c) time of travel from the highest point to the ground. Equation of motion is h"= -32, where h(t) is the height of projectile at moment t.
Solve the following using the 5-step process. The function H(t) = -16+2 +240t + 1216 gives the height (t), in feet, of a rocket t seconds after launching. The rocket is launched with an initial velocity 240 feet/sec from a hill that is 1216 feet high (a) How long does it take for the rocket to hit the ground? Instructions: Round your answer to the nearest whole number. When entering units, type the full word withou capitals, eg, feet, meters,...
A projectile is launched straight up from ground level with an initial velocity of v0 per sec. Neglecting air resistance, its height in feet, s, after t seconds after launch is given by the equation s = –16t2 + v0t. At what time(s) will the projectile reach a height of 112 feet when v0 = 96 feet/sec? After how many seconds will it return to the ground when v0 = 96 feet/sec?
A projectile is thrown upward so that its distance, in feet, above the ground after t seconds is h= -16t2+608t. What is its maximum height?
A projectile is thrown upward so that its distance above the ground after t seconds is h(t) = - 16/? +3121. After how many seconds does it reach its maximum height? O A. 10 sec OB. 6 sec OC. 26 sec O D. 19.5 sec
A projectile is launched from ground level with an initial velocity of v 0 feet per second. Neglecting air? resistance, its height in feet t seconds after launch is given by s equals negative 16 t squared plus v 0 t. Find the? time(s) that the projectile will? (a) reach a height of 80 ft and? (b) return to the ground when v 0 is 32 feet per second. ?(a) Find the? time(s) that the projectile will reach a height...
A projectile is launched from the top of a 75m-tall cliff with an initial velocity of 31m/s at an angle of 42° above the horizontal. For this problem, assume that the base of the cliff is at y 0 and that the projectile starts at x 0 on a standard xy plane 1. What is the maximum height above the ground that the projectile will achieve? 2. How long will it take for the projectile to reach its maximum height?...
40. A projectile is launched from the top of a building with an initial velocity of 10.0 m/s at an angle of 42.0 below the horizontal. The building is 34.0 meters tall, and it stands on level ground. Air resistance is negligible. Calculate (a) the distance traveled horizontally by the projectile by the time it hits the ground, and (b) the magnitude and direction of the projectile's velocity at the instant it arrives at the ground.
Fill in the Blanks A golf ball is projected upward from ground level at an initial velocity of 112 ft/sec. The height of a projectile can be modeled by s(t) = -16t+ vot + So, where t is time in seconds, So is the initial height in feet, and Vo is the initial velocity in ft/sec. a. How high will the ball be after 2 sec? O feet b. What is the maximum height the ball reaches? O feet c....
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4. Suppose a stone is launched vertically upward with initial velocity 32 ft/sec from a height of 48 ft above ground. After t seconds its height is given by s(t) = -16t2 + 32t + 48 At the time when the stone hits the ground it is moving with a speed of A. 32 ft/s B. 24 ft/s C. 64 ft/s D. 48 ft/s E. 96 ft/s