Question

The distance from the earth to the moon, Mars, and Jupiter is respectively 384x10Ⓡ, 55*10', and 588x10’meters. If a ship travels at a speed of 2x109 m/s, A) how long in seconds will it take to get to the A) Moon? B) Mars C)Jupiter You are near a lake. Wind speed is currently 8 m/s (-18 mph). There is smoke on the water. A) How far would the smoke travel in 30 minutes? B) The smoke came from some fire in the sky, which you are now starting to run away from. You start running at 2.0 m/s with a deceleration (AKA negative acceleration) of 0.0005 m/s?. How far did you run in 30 minutes? C) What is your speed after 30 minutes?

Answer 1

- = 192 S Solution 1) A) Distance of the Moon = 384 x 1o'm speed of the ship = 2x10 m/s Time taken by the ship to go to the Moon 384x100 2 x 100 B) Distance the Mars = 55x100 m. speed 55 x109 = 27500 S 2x100 c) Distance of the Jupiter = 588x10ºm Time taken by the ship = 588X10% = 294x109 . 2x100 of the Time taken by the ship =

Solution 2)A) let d be the distante travelledby the smoke in (30 minutes = 18008) speed of the wind= 8m/s i. d = 8 x 1800 = 14400m. id= 144oom solution 2) B) deacceleration = 0.0005 m/2 = a Let § d be the distance travelled by me in(30 minutes - 18005) i d = 2x1800 Ix ax (1800) Initial velocity 2 m/s. = U d = 2x 1800 - X 2 5 x 11800) 10000 2 d = 27gom. het V be my speed ofter (30 minutes = 1800s) :: V= 2 - (1800)*(0.0005) V = 1.1 m/s