Question

Problem 3 Two wires each carry 150.0 A of current and 1.2 cm apart. (a) Calculate the magnetic field 20 cm away at point 0, in the plane of the wire. (b) A current produces a magnetic field, and a magnetic field exerts a force on a current (wire). Therefore, two current-carrying wires will exert forces on each other. Illustrate the magnetic forces between the wires on figure 1 below. 0 20 cm I 12

Answer 1

4) field at Point d, The magnetic 20 cm to due انبیا Both wires be Ilk Id₂ | 1.2 cm IR B=B, + B₂ carrying a magnetic field wire at due to current Point ved distance away B = Mo I and so Mo = 4AX10 axio? Tm Mo Iz A Mo I, 2ad, + at dz Is = I also pl $B=f(4*x10)(150) + (46X16))(180) 0.2 m =>B= di = 26cm = 2x) (0.2) (28) (0-212) dz = (20 + 1.2) cm = 0.2126 [o.o 0.00015 + 0.000141509)T B= 0.000291509 T B= 2:9x10" , L The direction of magnetic field is given by A i = î x - where Ô direction of magnetic field î = = direction of current ô = direction of point from the wire field is inside foto So magnetic the paper,

The magnetic field at due to wire 1 wire - 2 In B = Mo I (@x8) 278 î, +62); > (9) ?> (-2); s); 6 9 foi Ho Il [(-1€)* (-5) 2ños B - Mo Il 27 ri Force oh current carrying wire in external field ha Icťx Too Force on wire 2 ez = lz (-12) B = B, (2) UTI NDO = Iz léz x) = Fz [ lz (-) * B, (2) = Iz lz B, 1960 067 force is upward Force wire - 1 will be downwards. Similarly The so BOTH WIRES ATTRACTS EACH OTHER I, wag due to W-2 fi = force on TA f = force on W-2 due to w-1 F2 Izt

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