Exercise 1. Tangent plane (15 pts) Let (S) be the surface given by the following equation....
i need justification please Exercise 1. Tangent plane (15 pts) Let (S) be the surface given by the following equation. x+y2 = 1+z2 An equation of the tangent plane to (S) at A(1,2,2) is: a. 2x + 4y – 4z = 1 b. x + y -z = 0 c. x + 2y – 2z = 1 d. x + y - z= 2 e. None of the above Exercise 3. Chain rule (15 pts) Let f(x,y,z) = xy +z...
Exercise 1. Tangent plane (15 pts) Let (5) be the surface given by the following equation. x2+y2 = 1+z2 An equation of the tangent plane to (S) at A(1,2,2) is: a. 2x + 4y – 4z = 1 b. x + y - z=0 c. x + 2y – 2z = 1 d. x + y - z = 2 e. None of the above a. b. C. O d. e.
Exercise 1. Tangent plane (15 pts) Let (5) be the surface given by the following equation. x2+y2 = 1+z2 An equation of the tangent plane to (S) at A(1,2,2) is: a. 2x + 4y – 4z = 1 b. x + y - z=0 c. x + 2y – 2z = 1 d. x + y - z = 2 e. None of the above a. b. C. O d. e. Exercise 2. Directional derivative (6 pts + 9 pts)...
Exercise 3. Chain rule (15 pts) Let f(x,y,z) = xy +z-5, x = r + 2s, y = 2r - sec(s),z=s af Then is: ar a. r - sec(s) b. sec(s) c. r+s+sec(s) d. 4r + 4s - sec(s) a. b. d.
Please Solve As soon as Solve quickly I get you thumbs up directly Thank's Abdul-Rahim Taysir Exercise 1. Tangent plane (15 pts) Let (5) be the surface given by the following equation x+y2 = 1 + z? An equation of the tangent plane to (S) at A(1,2,2) is a 2x + 4y - Az = 1 b. x + y - z=0 c. r + 2y - 2z = 1 d. x + y - z = 2 e. None...
Let f(x,y,z) = xy + z-5,x=r +2s, y = 2r - sec(s), z = s Then I is: ar a. r - sec(s) b. sec(s) c. r+s+sec(s) d. 4r + 4s - sec(s) a. b. C. Given zº – xy + y2 + y2 = 2 and z is a differentiable function in x and y. Then at (1,1,1) is: дх a. 0 b. 1 c. d. e. None of the above o a. o b. ♡ C. o d.
Exercise 2. Directional derivative (6 pts + 9 pts) Let f(x, y, z) = xy + y2 – 23 – 105. ... touch 25% 17:12 docs.google.com 2) The direction in which f decreases most rapidly at A(0,1,1) is: a. e. None of the above a. b. C. Exercise 3. Chain rule (15 pts) Let f(x,y,z) = xy +z-5,x=r+2s,y = 2r - sec(s),z=s
(1 point) Find the equation of the tangent plane to the surface z = y In(x) at the point (1. -9,0). Z- Note: Your answer should be an expression of x and y, e.g. 3x - 4y + 6.
Find an equation of the tangent plane to the surface f (x, y) = x tan y at the point (2, /4, 2). a. x - 4y - z = b. None of these c. x + 4y - z = - d. -x + 4y - z = e. - x + 4y - z = /4 We were unable to transcribe this imageWe were unable to transcribe this imageWe were unable to transcribe this imageWe were unable to...
Question 11 1 pts What is the equation of the tangent plane of the graph of the function f(x, y) = 2x cos y at the point (1,0, 2)? A) z = x – 2y + 2 B)z = 2x C)z = x + 2y – 2 D)z = 34 ОС OA о B