Question

Exercise 1. Tangent plane (15 pts) Let (S) be the surface given by the following equation. x+y2 = 1+z2


An equation of the tangent plane to (S) at A(1,2,2) is: a. 2x + 4y – 4z = 1 b. x + y -z = 0 c. x + 2y – 2z = 1 d. x + y - z=


Exercise 3. Chain rule (15 pts) Let f(x,y,z) = xy +z -5, x=r+2s, y = 2r – sec(s), z =s


af Then ar is: a. r - sec(s) b. sec(s) c. r+s+ sec(s) d. 4r + 4s – sec(s)

i need justification please

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Answer #1

(1) 2 2 Let (34,2)= ut 5-3-1, then of 221, 22, 23 > (1,2,3) 2 22 , Ч, Ч7 The equation of tangent Plane is 3(1-1) +y (9-2) – ч

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i need justification please Exercise 1. Tangent plane (15 pts) Let (S) be the surface given...
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