Question

A factorial experiment was designed to test for any significant differences in the time needed to perform English to foreign language translations with two computerized language translators. Because the type of language translated was also considered a significant factor, translations were made with both systems for three different languages: Spanish, French, and German. Use the following data for translation time in hours. Language Spanish French German System 1 8 10 12 12 14 16 System 2 6 14 16 10 16 22 Test for any significant differences due to language translator system (Factor A), type of language (Factor B), and interaction. Use a = .05. Complete the following ANOVA table (to 2 decimals, if necessary). Round your p-value to 4 decimal places. Source of Variation Sum of Squares Degrees of Freedom Mean Square F p-value Factor A Factor B Interaction Error Total The p-value for Factor A is Select your answer - What is your conclusion with respect to Factor A? - Select your answer - The p-value for Factor B is - Select your answer - What is your conclusion with respect to Factor B? - Select your answer - The p-value for the interaction of factors A and B is - Select your answer - What is your conclusion with respect to the interaction of Factors A and B? Select your answer -

Answer 1

BY USING SPSS >ANALYZE> GENERAL LINEAR MODEL

WE HAVE

Between-Subjects Factors N SYSTEM 6 6 LANGUAGE SYSTEM 1 SYSTEM 2 FRENCH GERMAN SPANISH 4 4 4 Tests of Between-Subjects Effects Dependent Variable VAR00002 Type III Sum Source of Squares df Mean Square Corrected Model 152.000" 5 30.400 Intercept 2028.000 2028.000 SYSTEM 12.000 12.000 LANGUAGE 114.000 2 57.000 SYSTEM * LANGUAGE 26.000 2 13.000 Error 52.000 6 8.667 Total 2232.000 12 Corrected Total 204.000 11 a. R Squared = .745 (Adjusted R Squared = .533) 1 1 F 3.508 234.000 1.385 6.577 1.500 Sig. .079 .000 .284 .031 .296

SOURCE	SS	DF	MS	F	P VALUE	DECISION
SYSTEM FACTOR A	12	1	12	1.39	0.2839	SINCE P VALUE > 0.05 DO NOT REJECT NULL HYPOTHESIS
LANGUAGE FACTOR B	114	2	57	6.6	0.0305	SINCE P VALUE < 0.05 DO REJECT NULL HYPOTHESIS
SYSTEM*LANGUAGE	26	2	13	1.5	0.2963	SINCE P VALUE > 0.05 DO NOT REJECT NULL HYPOTHESIS
ERROR	52	6	8.67
TOTAL	204	12-1=11