Question

Marked out of 6.00 Pidg queJLIUM Question 3 Not yet answered if a and b are constants, the solution of (aye axy +b)dx+(2ye axy + axy e axy – 1)dy=0 is Select one: a. ewy + bx=C o bye + bx-y= 0 O c. ye xy + bx-y=C odyexy +bx+y=C oe.y?e@y+bx = y o .yeasy + x-y=C o & ylemy -1)=C Oh.ye® + bx-y=C

Answer 1

axy axy (ay²e +b) dx + (aye axy ay ay :0. . (ays eaky +b) dx = -(2yeary + axy ery -1) dy integrate Scause aty tbl dx = f (i- a gyerty as axpory) ay a yeary dx + fb dr dx + fbdx = (dy - 2 fy eary (dy - 2 f g eary - ax fyle both side, tc fyears dy ef vov - fuilfuduldu. I here u = 4 V= e eaxy. yeux! ilyeth dy = yledy - Scuff eats dy dy. - s dy e dy ye Syreary dy ye/ eaxy dy-fc2y) (Seary dy) dy. ary e ах ary ax axy е ax (ax) 2. axy y² e axy ye dy. ax ах eary - eary axy ge ax 2 dx (ax Syeary dy = y² eaxy axy 2 ye + reary ax сак 2 (ax 6
I tried a lot but getting the same answer all the time as above.

so, I think there might be some problem with the option.