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A differential equation of the form M(x,y) dx + N(x,y) is said to be exact differential equation iff
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If a and b are constants, the solution of (ayže xy +b)dx + (2ye xy +...
If a and b are constants, the solution of (aye « +b)dx +(2ye xy + axy...
If a and b are constants, the solution of (aye « +b)dx +(2ye xy + axy e ay – 1)dy=0 is a. Select one: ..y?e@y+bx = y b.y?(exy - 1) = 0 o c.yle axy +bx+y=C O d. ye xy + bx-y=C oe.yle ax + bx-y=C of.yle xy +bx-y=C g. e ary+bx= c o h. ye xy + x-y=C
If a and b are constants, the solution of (aye axy +b)dx + (2ye axy +...
If a and b are constants, the solution of (aye axy +b)dx + (2ye axy + axy e axy – 1)dy=0 is Select one: a.y? (e axy – 1)=c b. ye ax + bx-y=c c. ye axy + x-y=C d. ye axy + bx=y e. ye axy + bx-y=C f. eaxy + bx = C g. y2e axy + bx+y=C h.yze axy + bx-y=c
IVI U OT 6.00 p Flag question If a and b are constants, the solution of...
IVI U OT 6.00 p Flag question If a and b are constants, the solution of (aye axy+b)dx+(2ye xy + axy’e x – 1)dy=0 is Select one: a.yle axy + bx-y=c b. eaxy + bx= c O c. ye axy + bx - y = c d. y2e xy + x - y=c e. ye ax + bx-y=C f. ye xy +bx+y=c g. y? (e axy - 1) = 0 h. Y x + bx = y
If a and b are constants, the solution of (ayaw+b)dx +(2ye KY + axy W -...
If a and b are constants, the solution of (ayaw+b)dx +(2ye KY + axy W - 1)dy =0 is Select one: O a.y?ery+bx+y=c O b. ew+bx=0 c. ye w+bx-y-c o d. ye ay+bx-y=C o e.ye+bx-yc 1.yev+x=y=C oy'+bx=y o hyl-1)0
Question 5 Not yet answered Marked out of 6.00 p Flag question If a and b...
Question 5 Not yet answered Marked out of 6.00 p Flag question If a and b are constants, the solution of (ayže xy +b)dx + 2ye xy + axy e x – 1 )dy=0 is Select one: O a.yle + bx-y=C O b. ye wy+x-y=C O ce@xy + bx=0 O d. ye xy + bx-y=C O e.y? (exy – 1)=C of.ye «xy +bx+y=C og-yle wy+bx-y=C oh.yle xy + bx=y
Marked out of 6.00 Pidg queJLIUM Question 3 Not yet answered if a and b are...
Marked out of 6.00 Pidg queJLIUM Question 3 Not yet answered if a and b are constants, the solution of (aye axy +b)dx+(2ye axy + axy e axy – 1)dy=0 is Select one: a. ewy + bx=C o bye + bx-y= 0 O c. ye xy + bx-y=C odyexy +bx+y=C oe.y?e@y+bx = y o .yeasy + x-y=C o & ylemy -1)=C Oh.ye® + bx-y=C
explain please 2. Which one of the following DE is exact? a. (x+y)dx+(xy+1) dy=0 b (e...
explain please
2. Which one of the following DE is exact? a. (x+y)dx+(xy+1) dy=0 b (e + y)<x+ſe+x)dy = 0 c.(ye* +1) dx +(e' + xy) dy = 0 d. (sin x+cos y) dx +(cos x +sin y) dy = 0 e. (eº+1) dx +(e? + 2) dy = 0 3. The solution of the following separable DE xy' =-y? is a. y= '+c b. y=- c. y = In x+c In x+c d. In y=x? + e. yer+C 4....
Please fast back, i don't have enough time if a and are constants, the solution of...
Please fast back, i don't have enough time
if a and are constants, the solution of Cayev+b)dx + 2ye WV + axy?owy - 1)dyo is Select one: O aye w+bx=y b.yo"4bx+y=c ce + bx-c od yox-y-c Oye "+bx-y-c oo"+bx-y=0 gye "+bx-y=c hyle-1)=0
The solution of the IVP dy dx = (ax+by+1)2 – 6; y(0)=0, where a € R...
The solution of the IVP dy dx = (ax+by+1)2 – 6; y(0)=0, where a € R and b ERVO} Select one: a. (ax +by+1)(1+x)= 1 O b. (ax+by+1)(1-x)=3 O c. (ax+by+1)2(1 - bx)=1 2 O d. (ax +by+1)= 1- bx e. (ax+by+1)(1-bx)= 1 of. (ax +by+1) (1 -bx)2 = 1 о g. (ax +by-1)(1-bx) = 1 O h. ax + by=1
The solution of the IVP dy dx = (ax+by+1)2 - Ø; y(D)=0, where a ER and...
The solution of the IVP dy dx = (ax+by+1)2 - Ø; y(D)=0, where a ER and b ERVO) is Select one: a. ax+by=1 b. (ax+by+1)(1-bx) - 3 c. (ax+by-1)(1 - bx)= 1 d. (ax +by+1)(1 - bx)2 = 1 e. (ax+by+1)(1-bx)= 1 2 f. (ax+by+1)= 1-bx g. (ax+by+1) (1 - bx)= 1 h. (ax+by+ 1)(1+bx) = 1 O O
If a and b are constants, the solution of (aye « +b)dx +(2ye xy + axy e ay – 1)dy=0 is a. Select one: ..y?e@y+bx = y b.y?(exy - 1) = 0 o c.yle axy +bx+y=C O d. ye xy + bx-y=C oe.yle ax + bx-y=C of.yle xy +bx-y=C g. e ary+bx= c o h. ye xy + x-y=C
If a and b are constants, the solution of (aye axy +b)dx + (2ye axy + axy e axy – 1)dy=0 is Select one: a.y? (e axy – 1)=c b. ye ax + bx-y=c c. ye axy + x-y=C d. ye axy + bx=y e. ye axy + bx-y=C f. eaxy + bx = C g. y2e axy + bx+y=C h.yze axy + bx-y=c
IVI U OT 6.00 p Flag question If a and b are constants, the solution of (aye axy+b)dx+(2ye xy + axy’e x – 1)dy=0 is Select one: a.yle axy + bx-y=c b. eaxy + bx= c O c. ye axy + bx - y = c d. y2e xy + x - y=c e. ye ax + bx-y=C f. ye xy +bx+y=c g. y? (e axy - 1) = 0 h. Y x + bx = y
If a and b are constants, the solution of (ayaw+b)dx +(2ye KY + axy W - 1)dy =0 is Select one: O a.y?ery+bx+y=c O b. ew+bx=0 c. ye w+bx-y-c o d. ye ay+bx-y=C o e.ye+bx-yc 1.yev+x=y=C oy'+bx=y o hyl-1)0
Question 5 Not yet answered Marked out of 6.00 p Flag question If a and b are constants, the solution of (ayže xy +b)dx + 2ye xy + axy e x – 1 )dy=0 is Select one: O a.yle + bx-y=C O b. ye wy+x-y=C O ce@xy + bx=0 O d. ye xy + bx-y=C O e.y? (exy – 1)=C of.ye «xy +bx+y=C og-yle wy+bx-y=C oh.yle xy + bx=y
Marked out of 6.00 Pidg queJLIUM Question 3 Not yet answered if a and b are constants, the solution of (aye axy +b)dx+(2ye axy + axy e axy – 1)dy=0 is Select one: a. ewy + bx=C o bye + bx-y= 0 O c. ye xy + bx-y=C odyexy +bx+y=C oe.y?e@y+bx = y o .yeasy + x-y=C o & ylemy -1)=C Oh.ye® + bx-y=C
explain please
2. Which one of the following DE is exact? a. (x+y)dx+(xy+1) dy=0 b (e + y)<x+ſe+x)dy = 0 c.(ye* +1) dx +(e' + xy) dy = 0 d. (sin x+cos y) dx +(cos x +sin y) dy = 0 e. (eº+1) dx +(e? + 2) dy = 0 3. The solution of the following separable DE xy' =-y? is a. y= '+c b. y=- c. y = In x+c In x+c d. In y=x? + e. yer+C 4....
Please fast back, i don't have enough time
if a and are constants, the solution of Cayev+b)dx + 2ye WV + axy?owy - 1)dyo is Select one: O aye w+bx=y b.yo"4bx+y=c ce + bx-c od yox-y-c Oye "+bx-y-c oo"+bx-y=0 gye "+bx-y=c hyle-1)=0
The solution of the IVP dy dx = (ax+by+1)2 – 6; y(0)=0, where a € R and b ERVO} Select one: a. (ax +by+1)(1+x)= 1 O b. (ax+by+1)(1-x)=3 O c. (ax+by+1)2(1 - bx)=1 2 O d. (ax +by+1)= 1- bx e. (ax+by+1)(1-bx)= 1 of. (ax +by+1) (1 -bx)2 = 1 о g. (ax +by-1)(1-bx) = 1 O h. ax + by=1
The solution of the IVP dy dx = (ax+by+1)2 - Ø; y(D)=0, where a ER and b ERVO) is Select one: a. ax+by=1 b. (ax+by+1)(1-bx) - 3 c. (ax+by-1)(1 - bx)= 1 d. (ax +by+1)(1 - bx)2 = 1 e. (ax+by+1)(1-bx)= 1 2 f. (ax+by+1)= 1-bx g. (ax+by+1) (1 - bx)= 1 h. (ax+by+ 1)(1+bx) = 1 O O
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