IVI U OT 6.00 p Flag question If a and b are constants, the solution of...
If a and b are constants, the solution of (aye axy +b)dx + (2ye axy + axy e axy – 1)dy=0 is Select one: a.y? (e axy – 1)=c b. ye ax + bx-y=c c. ye axy + x-y=C d. ye axy + bx=y e. ye axy + bx-y=C f. eaxy + bx = C g. y2e axy + bx+y=C h.yze axy + bx-y=c
If a and b are constants, the solution of (aye « +b)dx +(2ye xy + axy e ay – 1)dy=0 is a. Select one: ..y?e@y+bx = y b.y?(exy - 1) = 0 o c.yle axy +bx+y=C O d. ye xy + bx-y=C oe.yle ax + bx-y=C of.yle xy +bx-y=C g. e ary+bx= c o h. ye xy + x-y=C
Question 5 Not yet answered Marked out of 6.00 p Flag question If a and b are constants, the solution of (ayže xy +b)dx + 2ye xy + axy e x – 1 )dy=0 is Select one: O a.yle + bx-y=C O b. ye wy+x-y=C O ce@xy + bx=0 O d. ye xy + bx-y=C O e.y? (exy – 1)=C of.ye «xy +bx+y=C og-yle wy+bx-y=C oh.yle xy + bx=y
Marked out of 6.00 Pidg queJLIUM Question 3 Not yet answered if a and b are constants, the solution of (aye axy +b)dx+(2ye axy + axy e axy – 1)dy=0 is Select one: a. ewy + bx=C o bye + bx-y= 0 O c. ye xy + bx-y=C odyexy +bx+y=C oe.y?e@y+bx = y o .yeasy + x-y=C o & ylemy -1)=C Oh.ye® + bx-y=C
If a and b are constants, the solution of (ayže xy +b)dx + (2ye xy + axy e xy – 1)dy=0 is Select one: oa.yle xy + x-y=C O b.yle xy +bx+y=C O c. y2exy – 1)=C O d. ye xy + bx-y=C O e.yle xy + bx=y f. e xy + bx=C O g. yle" + bx-y=C O h. ye xy + bx-y=C
If a and b are constants, the solution of (ayaw+b)dx +(2ye KY + axy W - 1)dy =0 is Select one: O a.y?ery+bx+y=c O b. ew+bx=0 c. ye w+bx-y-c o d. ye ay+bx-y=C o e.ye+bx-yc 1.yev+x=y=C oy'+bx=y o hyl-1)0
Please fast back, i don't have enough time if a and are constants, the solution of Cayev+b)dx + 2ye WV + axy?owy - 1)dyo is Select one: O aye w+bx=y b.yo"4bx+y=c ce + bx-c od yox-y-c Oye "+bx-y-c oo"+bx-y=0 gye "+bx-y=c hyle-1)=0
Flag question Marked out of 6.00 Question 1 dy The solution of the IVP = (ax+by+1) where a ER and b ERVO) is bi y0)=0, Select one a. (ax + by - 1)(1-x-1 b. (ax+by+1)(1+x)=1 clax+by + 1) (1 -bx=1 dax+by = 1 lox+by+1 (1 -bx) = 1 2 Olax+by+1)- 1-bx (x+by+ 1X1 - bx) = 3 (ax+by+ 1X1 -bx) = 1 Ne
explain please 2. Which one of the following DE is exact? a. (x+y)dx+(xy+1) dy=0 b (e + y)<x+ſe+x)dy = 0 c.(ye* +1) dx +(e' + xy) dy = 0 d. (sin x+cos y) dx +(cos x +sin y) dy = 0 e. (eº+1) dx +(e? + 2) dy = 0 3. The solution of the following separable DE xy' =-y? is a. y= '+c b. y=- c. y = In x+c In x+c d. In y=x? + e. yer+C 4....
Need fast help ?? Question 2 Not yet answered Marked out of 6.00 Flag question a dy If a ERK-1) and DER {1}, the solution of x dx + a+1 y=- 1-b -xy is 1-b Select one: oa.y? -b = x+C+xa O b.y =x+C+xQ-1 O cyl-= x+cx-a ody-b = x+C+x-a o e.yt-b=C+x-a of.y? -B=x+c g. y = x+C+x-a oh.y0 - 1 = x+C+xa