Question

< Question 19 of 22 > Calculate the density of carbon monoxide, CO, at STP. Assume ideal behavior. density: g/L

Answer 1

Densitges is mass (m) per unit volume (V). It measures how much mass (m) is contained in given wolume (v) u as Now at STP, one mole of Mars of one mole occupies 22.4 liters gas of co= molar mars of t molar mans of o = 12.01 g/mol + 16.009/mol = 28.019/mol 28.01 g I mole of co is ao a3 28.01 g 22.4 L = 1.25 g/L 20 8o4.4g is of Cry = Mass of chy Molar mans 16.04 g/mol Mars of chy Number of moles of Chy, n= molar mass of cry 204.4 g 16.04 g/mol of h - So. 15 mol 0.760 L T = 209.8k Applying ideal gas equation, we have PV=nRT NRT P-

R = .002 L-atry K-mol 50.15 8.082 x 209.8 =1135.2 atm 0.760 2) reaction 2 C8 Hig(e) + 25 O2(g) → 16 CO2 (8) + 18420 (es According 2 moles of Co His produe 16 moles of Lo, 603 moles of will produce x 603 (8 H18 2 ie 4824 moles For co2 P = 0.995 atm T = 12.0°C = 12 + 273 = 285k = 4824 082 bratom K-mol Vs? Applying lane, we have gas PV = nRT ARI = 4824x: 0826285 0.995 112736.88 0.995 113303.3 L