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Question 20 (5 points) Using the following standard reduction potentials: PbO2 + 4H+ + SO42- + 2e → PbSO4(s) + 2H20 E° = +1.6
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(20 We can arrange the given sin as Pb S04 (3) +2H2O » Pbba + 4h + sou + 2€ {=-1.69V pboat yht+ge Phat + 2H30 E = 1.46V over

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