Elimination of H2O is in forward direction .
and when we will add H2O in product of forward reaction it will form starting reactant of 1st reaction so that is a reverse reaction so addition of H2O is reverse reaction
What type of reaction is in the forward direction? What type is in the reverse direction?...
A reaction that can proceed in either the forward or the reverse direction as written is called a ________ reaction. Question 2 options: microscopic solid phase favored reversible miniscule
1A) What type of reaction occurs at 2? phosphorylation Isomerization hydrolysis oxidation-reduction dephosphorylatioN 1B) What type of reaction occurs at 7? phosphorylation Isomerization hydrolysis oxidation-reduction dephosphorylation A B CHO он с CH, OH D Нc-o-Po, сно -он н го о H HO -н 2 но- -H 3 н- -он H но -H н -он н -он нс-о-ро, он он но H H -он н он нс-о-ро, н -он н CH,OH нс-о-ро, H G ОРО, 7 6 F E CHO нс-о-РО,...
For an endothermic forward reaction (ΔHforward>0 ), the activation energy of the reverse reaction will be equal to: Select the correct answer below: Ea of the forward reaction Ea of the forward reaction plus ΔHforward. Ea of the forward reaction minus ΔHforward none of the above
Q1: A reaction that can proceed in either the forward or the reverse direction as written is called a - reaction. 1) Favored 2) Miniscule 3) reversible 4) Solid-phase 5) Microscopic Q2: 2502(g) + O2(g) = 2503(g) For the reaction at equilibrium, if Oz is added, the amount of SO2 present will 1) Decrease 2) Increase 3) Stay the same Q3: For the following equilibrium reaction, which causes and effect are correctly matched? CO(g) + 2H2(g) = CH3OH(g) + heat...
Suppose the reaction A <---> B in the forward direction is first order in A and the rate constant is 1.50 x 10-2s-1. The reverse reaction is first order in B and the rate constant is 4.50 x 10-2s-1 at the same temperature. What is the value of the equilibrium constant for the reaction A <---> B at this temperture?
where the forward and reverse reaction rates are expressed as Forward rate =-k,[CO][H2ofto2r25 Reverse rate =-k,[CO2] where 1.674- 10J/kmol) kr = 2.24 . 10121 (kmol)-0.751 exp R, T (K) -1.674. 10*J/kmol) R,T(K) k, = 5.0 . 108(-) exp where the brackets represent concentration ie. [CO] is the concentration of our basis CO. Note from the proposed mechanism above, that water (H20) is really acting as a catalyst (it is not consumed or generated in the reaction) and you are interested...
What must be true if the forward reaction is occurring more rapidly than the reverse reaction?The reaction is not reversible.Q<KQ=KThere are no products present.
Suppose the below reaction in the forward direction is first order in A and the rate constant is 1.30×10-2 s–1. The reverse reaction is first order in B and the rate constant is 4.50×10-2 s–1 at the same temperature. What is the value of the equilibrium constant for the below reaction at this temperature?
For questions #47- 53: Name the following molecules. IUPAC names only - no "common chemical" names. 47). re H 48). 49). cu он CH3 50). CH-OH 1 1 1 CH2 CH₂ 51). он 52). нннн Hн н-с-с-с-с-о-с-с-н нннн Hн 53). ОН ОН ОН T ТІ H— c— c— сен 1 T н Н н 1
Could you please write this reaction in reverse with all the intermediate steps? Thank you H 4.Е. -- . "Сега HO) он2 -Н,0 OMe Омо -Н,0° propanoic acid Сн ,он