Question

could i please get help with these thanks!

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Question Help Archer studying public opinion of proposed Social Security changes obtains a simple random sample of 30 adult Americans and ask them whether or not they support the proposed changes to say that the distribution of the sample proportion of adults who respond yes, is approximately normal, how many more adult Americans does the researcher need to sample in the following (a) 10% of all adult American support the changes 0.) 19% of all adult American support the changes (A) The researcher must ask more Americants (Round up to the wester)

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Answer 1

Given data :- n.30 = 0.1 a P = 10% np (1-P) = 10 P(1-P) ? 10 =) 0.1(1-0-1) = ols n 10 10 0.097 = nz n 0.9 112 nz 111.11 Required number of additional adults = 112 -30 = [82 b) P=15% = 0.15 >10 np (1-P) P(1-P) sla =) 0.15*(1-015) = 10 . 1275 그음 na 10 0.1275 => n s 78.43 n=79 Required number of additional acuits = 79-30 49 2 M2150 P=0.4 9-1-pc 10:4= 0.6 np: 150x0.4 = 60 > 10 n30.0ny20000 - 1000 ng = 150x0 6 = 90 910 150 n < 1000 Approcimately nomal because neo.05 N and upli-1/210 elp P = 10.4 op PC-P) -0.040000 054 x0.6 2 150

Given n=400 X = 204 P = 0-49 P (2 > 2014) Mean ll= np 400 x0U9 2,196 S.D - 204-196 10 os Joplit) - JHOC'xo: 49x (roing) = 9,998 =10 P(x > 204) 1-P[22 ] =4-p[22 =1-Plze > 1-P[208] from a table we get P[2208] 8 iN 0-7881 -:|- 0.788 / 20:2119 Probability P=0.2119 P=021