Question

An object is placed 50.0cm in front of a lens. The image forms on the same side of the lens and is larger than the object. The image is (upright or inverted), the lens is (converging/diverging), image distance is (positive/negative), the image is (real, virtual) O inverted, diverging, positive, real upright, converging, positive, virtual inverted, converging, positive, virtual upright, converging, positive, real upright, converging, negative, virtual upright, converging, negative, real inverted, converging, positive, real O inverted, diverging, negative, real

Answer 1

if the image is larger than the object size then it is a virtual and upright image

it happends only when the object is placed less than the focal point in the case of converging lens

and image distance is negative because the refracted rays are not passing through the image point

so answer is

upright, converging, negative and virtual