A charge, q=91.0000 microCoulombs on a particle with mass m=1.00000 milli- grams, moves through a pipe...
A charge, q=91.0000 microCoulombs on a particle with mass m=1.00000 milli- grams, moves through a pipe from the origin to a point at coordinate x=1.40000m and y=1.8000m. All space is filled with a uniform electric field E=1,900.00000N/C and pointing parallel to the x axis. What is the change in electric potential as the mass moves from initial to final positions (in VOLTS)
A charge, q=71.0000 microCoulombs on a particle with mass m=10.00000 milli- grams, moves through a pipe from the origin to a point at coordinate x=2.00000m and y=0.6000m. All space is filled with a uniform electric field E=400.00000N/C and pointing parallel to the x axis. What is the change in electric potential as the mass moves from initial to final positions (in VOLTS)
A charge, q=51.0000 microCoulombs on a particle with mass m=8.00000 milli- grams, moves through a pipe from the origin to a point at coordinate x=1.00000m and y=0.2000m. All space is filled with a uniform electric field E=900.00000N/C and pointing parallel to the x axis. What is the change in electric potential as the mass moves from initial to final positions (in VOLTS) Your Answer:
An object is placed 50.0cm in front of a lens. The image forms on the same side of the lens and is larger than the object. The image is (upright or inverted), the lens is (converging/diverging), image distance is (positive/negative), the image is (real, virtual) O inverted, diverging, positive, real upright, converging, positive, virtual inverted, converging, positive, virtual upright, converging, positive, real upright, converging, negative, virtual upright, converging, negative, real inverted, converging, positive, real O inverted, diverging, negative, real
An object is placed 50.0cm in front of a lens. The image forms on the same side of the lens and is larger than the object. The image is (upright or inverted), the lens is (converging/diverging), image distance is (positive/negative), the image is (real, virtual) O upright, converging, positive, virtual O inverted, converging, positive, real inverted, diverging, negative, real O upright, converging, negative, virtual O inverted, diverging, positive, real O inverted, converging, positive, virtual O upright, converging, positive, real O...
Question 18 (8 points) An object is placed 50.0cm in front of a lens. The image forms on the same side of the lens and is larger than the object. The image is (upright or inverted), the lens is (converging/diverging), image distance is (positive/negative), the image is (real, virtual) upright, converging, negative, real inverted, converging, positive, virtual upright, converging, negative, virtual upright, converging, positive, virtual upright, converging, positive, real O inverted, converging, positive, real inverted, diverging, positive, real inverted, diverging,...
Please help with this 4 part question Light with wavelength = 700.0000nm is incident on a double slit with spacing d=50.00000micrometers. The distance to the screed is 0.5000meters. What is the spacing between neighboring constructive fringes near the center of the screen? (in meters) Light with wavelength 500nm is incident upon a surface at an angle of 40.0 degrees, refracts and enters a second medium. The light that enters the second medium travels faster than in the first medium. Compared...
A lens located in the y-z plane at x = 0 forms an image of an arrow at x = x2 = 112.4 cm. The tip of the object arrow is located at(x,y) = (x1, y1) = (-45.9 cm, 4.91 cm). The index of refraction of the lens is n = 1.43.1) What is flens, the focal length of the lens? If the lens is converging flens is positive. It the lens is diverging, flens is negative.2) What is y2,...
Consider an object with s=12cm that produces an image with s′=15cm. Note that whenever you are working with a physical object, the object distance will be positive (in multiple optics setups, you will encounter "objects" that are actually images, but that is not a possibility in this problem). A positive image distance means that the image is formed on the side of the lens from which the light emerges.Part AFind the focal length of the lens that produces the image...
A system of two lenses forms an image of an arrow at x = x3 = 57.9 cm. The first lens is a diversing lens located at x = 0 and has a focal length of magnitude f. = 12.4 cm. The second tens is located atx=27=25.8 cm and has an unknown focal length. The tip of the object arrow is located at (x,y) = (x, y) = (-36.6 cm, 12.1 cm). 1) What is xi, the x co-ordinate of...