given data
frequency f = 60 Hz
capacitance C = 2 μF = 2x10-6 F
Resistance R = 1500 Ω
Inductance L=8 H
We know that ꞷ = 2πf = (2)(3.142)(60) = 377 rad/s
we know that
inductive reactance XL = ꞷL = (377)(8H) =3016 Ω
capacitive reactance XC = 1/ꞷC = 1/(377)(2x10-6 ) = 1,326.26 Ω
We know that series LCR circuit impedence is
Z = ( R2 + (XL - XC)2 ) 1/2
Plugging the values in the formula
Z = ((1500)2 +(3016-1,326.26)2)1/2 = 2259 Ω = 2.26 k Ω = approximately =2.30 k Ω
Z = 2.30 k Ω
ans is
impedence is Z = 2.30 k Ω |
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