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A certain computer becomes inoperable if two components A and B both fail. The probability that A fails is 0.018 and the prob
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Answer #1

Probability that A fails P(A) = 0.018

Probability that B fails P(B) = 0.043

Probability that B fails when A fails P(B/A) = 0.043 * 7 = 0.301

Probability that the computer becomes inoperable is P( A \cap B) = P(A)*P(B/A) = 0.018 * 0.301 = 0.00542

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