Question

PROBABILITY AND ENGINEERING STATISTI Dashboard / My courses / PROBABILITY AND ENGINEERING STATISTICS-1194-meta / Chapter Or Question 1 Quiz n tion Not yet answered 1 2. A certain computer becomes inoperable if two components A and B both fail. The probability that A fails is 0.012 and the probability that B fails is 0.026. However, the probability that B fails increases by a factor of 5 if A has failed. Calculate the prochaibility that computer A fails if B has failed. Marked out of 5.00 Finish ati P Flag question Time left [The answer should be a number rounded to five decimal places, don't use symbols such as %] Next page

Please Solve As soon as
Solve quickly I get you thumbs up directly
Thank's
Abdul-Rahim Taysir

Answer 1

Let X be the event that A has failed and Y be the event that B has failed.

We have to find P(X|Y) = P(X and Y)/P(Y)

P(Y) = (0.012)(0.13)+(0.988)(0.026) = 0.00156+0.25688 = 0.25844

P(X and Y) = (0.012)(0.13) = 0.00156

Hence the required probability = 0.00156/0.25844 = 0.00603

Hence the probability that computer A fails if B has failed = 0.00603