Answer: Assuming that random variable X is normally distributed with μ = 120 and σ = 20
Solution:
P(80 < X < 100) = P(80-120/20 < Z < 100-120/20)
P(80 < X < 100) = P(-2 < Z < -1)
P(80 < X < 100) = P(Z < -1) - P(Z < -2)
P(80 < X < 100) = 0.15866 - 0.02275
P(80 < X < 100) = 0.13591
The third option is correct answer.
P(80 < X < 100) = 0.1359
Assuming that random variable X is normally distributed with u = 120 and o =20, the...
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