Question

Question 1 0/1 pts Aladder leans against a wall, an angle theta from the horizontal direction. (that is, theta =0 would mean horizontal). The ladder has mass M, and a person of mass m stands at the center of the ladder. What is the minimum necessary coefficient of static friction mu_s with the ground, such that the ladder will not slip out? sin(theta) / (2 cos(theta)) cos(theta)/(2 sin(theta)) Msin(theta)/(2(M+m) cos(theta)) Mcos(theta)/(2(M+m) sin(theta)) 0 1 1 nts

Answer 1

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N, 28 mg P mo Apply translational Equilibrin Along horizontal, f-N => Ms Ng = Ni Nz Mr = Ni N2 f = Ms Na Along vertical, mg + Mg = N₂ => N = (M+ m)g & Aply estational equilibrium. is Not torque about any point is zero. Take torque about 'P', {Torque = force X to distance} Mg x loco +mgxlue - Nxesine so (M&M) g caso = N, sino - (n) Mg = (M+ m) g% coto (M+ m)g coto