Question 11)
Since pH of any solution is calculated by fomula
pH = -log[H3O+] or pH = -log[H+]
a) For 4.2*10-4 M
pH = -log(4.2*10-4)
= 3.3767 = 3.38
Hence pH of solution will be 3.38
b) pH = -log(5.7*10-6)
= 5.2441 = 5.24
Hence pH of solution will be 5.24
c) pH = -log(3.6*10-9)
= 8.4436 = 8.44
Hence pH of solution will be 8.44
d) pH = -log(1.2*10-12)
= 11.9208 = 11.92
Hence pH of solution will be 11.92
In multiple questions we solve only one question at a time. Thanks
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